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5. Calculate the concentration of calcium ions in a saturated calcium phosphate solution. 
(

K

sp

 for Ca

3

(PO

4

)

2

 = 1.3 X 10

-26

)  

a.

 

1.2 x 10

-5

 mol/L  

b.

 

2.0 x 10

-5

 mol/L  

c.

 

6.6 x 10

-6

 mol/L  

d.

 

7.8 x 10

-6

 mol/L  

e.

 

8.3 x 10

-6

 mol/L  

6. Calculate the molar solubility of silver carbonate in 1.0 

M

 sodium carbonate solution.  

(

K

sp

 for Ag

2

CO

3

 = 8.1 x 10

-12

)  

a.

 

8.1 x 10

-12

 

M

  

b.

 

2.8 x 10

-6

 

M

  

c.

 

1.4 x 10

-6

 

M

  

d.

 

1.4 x 10

-8

 

M

 

e.

 

2.0 x 10

-4

 

M

 

7. Calculate the pH of a solution necessary to just begin the precipitation of Mg(OH)

2

 

when [Mg

2+

] = 0.001 

M

. (

K

sp

 for Mg(OH)

2

 = 1.2 x 10

-11

a. 11 

 

b. 10  
c. 9 

 

d. 8  
e. 4 

 8. In qualitative analysis, the metals of Ion Group 1 can be separated from other ions by 
precipitating them as chloride salts. A solution initially contains Ag

+

 and Pb

2+

 at a 

concentration of 0.10 

M

. Aqueous HCl is added to this solution until the Cl

-

 concentration 

is 0.10 

M

. What will the concentrations of Ag

+

 and Pb

2+

 be at equilibrium? 

(

K

sp 

for AgCl = 1.8 x 10

-10

K

sp

 for PbCl

2

 = 1.7 x 10

-5

)  

a. [Ag

+

] = 1.8 x 10

-11 

M

; [Pb

2+

] = 1.7 x 10

-6 

M

  

b. [Ag

+

] = 1.8 x 10

-7 

M

; [Pb

2+

] = 1.7 x 10

-4 

M

  

c. [Ag

+

] = 1.8 x 10

-11 

M

; [Pb

2+

] = 8.5 x 10

-5 

M

  

d. [Ag

+

] = 1.8 x 10

-9 

M

; [Pb

2+

] = 1.7 x 10

-3 

M

  

e. [Ag

+

] = 1.8 x 10

-9 

M

; [Pb

2+

] = 8.5 x 10

-6 

M

  

9. Silver chloride is relatively insoluble in water (

K

sp

 for AgCl = 1.8 x 10

-10

) but it is 

soluble in aqueous ammonia, due to the formation of the complex ion Ag(NH

3

)

2

+

. How 

many moles of AgCl will dissolve in 1.00 L of solution containing 6.0 moles of free 
NH

3

? (

K

f

 for Ag(NH

3

)

2

+

 = 1.7 x 10

7

)  

a.  9.1 x 10

-6

 mol  

b.  2.9 x 10

-4

 mol  

c. 0.0091 mol 

 

d. 0.084 mol  
e. 0.33 mol 

 

Comments:

Multiple choice questions in General Chemistry

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